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x_calculation_step vs convolution_step
rowlesmr #1
Member since Oct 2011 · 245 posts
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Subject: x_calculation_step vs convolution_step
In my specific case, I've got constant step-width data, but in general:

Is there any difference between saying
x_calculation_step = Yobs_dx_at(Xo);
convolution_step = n;

or

x_calculation_step = Yobs_dx_at(Xo)/n;
convolution_step = 1;

for any number n > 1?
--
Matthew
AlanCoelho #2
Member since Aug 2011 · 323 posts
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There is a difference.

The x_calculation_step applies to all equations involving Ycalc.

convolution_step changes the peak_calculation_step which affects convolutions only.

convolution_step also divides the peak_calculation_step such that the original data points coincide with the new data points.

The above means that using convolution_step is a lot quicker than using changing x_calculation_step; additionally it is more accurate if x_calculation_step does not have the new data points coinciding with the original data points.
rowlesmr #3
Member since Oct 2011 · 245 posts
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Thanks

I'll have to experiment a bit with my low-res quant data.
--
Matthew
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